(2x-4)^2+5=32

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Solution for (2x-4)^2+5=32 equation: 



(2x-4)^2+5=32

We move all terms to the left:

(2x-4)^2+5-(32)=0

We add all the numbers together, and all the variables

(2x-4)^2-27=0

We move all terms containing x to the left, all other terms to the right

(2x-4)^2=27

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